Project:Deactivating a ferric chloride solution: Difference between revisions
From London Hackspace Wiki
Project:Deactivating a ferric chloride solution (view source)
Revision as of 12:36, 25 May 2010
, 25 May 2010→In Theory
(Created page with 'Project maintained by Daniel Sikar ~/ dsikaratgmaildotcom. == Deactivating a Ferric Chloride solution == === In practice === * Example A solution that was made with a packet o…') |
|||
| Line 42: | Line 42: | ||
To find how many moles are contained in 300 grams of Ferric Chloride the calculation is 300/162.3 = 1.85 moles of Ferric Chloride. | To find how many moles are contained in 300 grams of Ferric Chloride the calculation is 300/162.3 = 1.85 moles of Ferric Chloride. | ||
Each mole of FeCl3 requires 3 moles of NaOH (Sodium Hydroxide) at 40 grams per mole. | |||
The weight of Na0H required to deactivate the spent FeCl3 solution is obtained thus: | |||
1.85 * 3 = 5.55 moles of NaOH, at 40 g/mole that will be 5.55 * 40 = 222 grams NaOH | |||
