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Project:Deactivating a ferric chloride solution: Difference between revisions
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Project:Deactivating a ferric chloride solution (view source)
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1.85 * 3 = 5.55 moles of NaOH, at 40 g/mole that will be 5.55 * 40 = 222 grams NaOH. | 1.85 * 3 = 5.55 moles of NaOH, at 40 g/mole that will be 5.55 * 40 = 222 grams NaOH. | ||
